I need help with (c) portion of the question.. nita or 2-2 MyStatLab: Module Two
ID: 3154888 • Letter: I
Question
I need help with (c) portion of the question..
Explanation / Answer
Mean ( u ) =123
Standard Deviation ( sd )=11
Number ( n ) = 38
Normal Distribution = Z= X- u / (sd/Sqrt(n) ~ N(0,1)
P(X > 119) = (119-123)/11/ Sqrt ( 38 )
= -4/1.784= -2.2416
= P ( Z >-2.2416) From Standard Normal Table
= 0.9875
P(X < = 119) = (1 - P(X > 119)
= 1 - 0.9875 = 0.0125
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