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t Test of Difference Means for Unequal Variance
Set Up Hypothesis
Null Hypothesis , There Is No-Significance between them Ho: u1 = u2
Alternate Hypothesis, There Is Significance between them - H1: u1 != u2
Test Statistic
X(Mean)=75.2
Standard Deviation(s.d1)=13.4396 ; Number(n1)=10
Y(Mean)=89.6
Standard Deviation(s.d2)=16.0222; Number(n2)=10
we use Test Statistic (t) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
to =75.2-89.6/Sqrt((180.62285/10)+(256.71089/10))
to =-2.2
| to | =2.2
Critical Value
The Value of |t | with Min (n1-1, n2-1) i.e 9 d.f is 2.262
We got |to| = 2.17749 & | t | = 2.262
Make Decision
Hence Value of |to | < | t | and Here we Do not Reject Ho
P-Value: Two Tailed ( double the one tail ) - Ha : ( P != -2.1775 ) = 0.057
Hence Value of P0.05 < 0.057,Here We Do not Reject Ho
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