For each of the following situations give the degrees of freedom and an appropri
ID: 3154513 • Letter: F
Question
For each of the following situations give the degrees of freedom and an appropriate bound on the P-value (give the exact value if you have software available) for the 2 statistic for testing the null hypothesis of no association between the row and column variables.
(a) A 2 by 2 table with 2 = 0.99.
df =
P-value =
(b) A 4 by 4 table with 2 = 17.53.
df =
P-value =
(c) A 2 by 8 table with 2 = 22.7.
df =
P-value =
(d) A 5 by 3 table with 2 = 13.2.
df =
P-value =
Please show work confused on how to solve....
Explanation / Answer
(a)df=(row-1)*(column-1)=(2-1)*(2-1)=1
Using a P Value from Chi-square Calculator, The P-Value is 0.319742. The result is not significant at p < 0.05.
(b)df=(4-1)*(4-1)=9
Using a P Value from Chi-square Calculator, The P-Value is 0.041035. The result is significant at p < 0.05.
(c)df=(2-1)*(8-1)=7
Using a P Value from Chi-square Calculator, The P-Value is 0.001922. The result is significant at p < 0.05.
(e)df=(5-1)*(3-1)=8
Using a P Value from Chi-square Calculator, The P-Value is 0.105151. The result is not significant at p < 0.05.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.