1. A box contains 34 parts, of which 7 are defective and 27 are nondefective. 2
ID: 3154445 • Letter: 1
Question
1. A box contains 34 parts, of which 7 are defective and 27 are nondefective. 2 parts are selected without replacement.
(a) The two events, the first draw and the second draw, are
independent, and the special multiplication rule applies.not independent, and the general multiplication rule applies. independent, and the general multiplication rule applies.not independent, and the special multiplication rule applies.
(b) Find the probability P(both are defective). (Give your answer correct to two decimal places.)
(c) Find the probability P(neither is defective). (Give your answer correct to two decimal places.)
2. A very proficient pistol marksman can hit the bullseye of a target at 75 yards 53% of the time. (Give all answers to 2 decimal places unless otherwise specified.)
a. What is the probability that he hits the bullseye on his first shot?
b. What is the probability he will hit the bullseye on is first and second shot?
c. What is the probability that he not hit the bullseye on his first and second shot?
d. What is the probability he will get his first bullseye on his third shot?
e. What is the probability he will hit the bullseye five times in a row?
f. What is the probability that he will get at least one bullseye is five tries? Hint: Use the complement rule.
Explanation / Answer
1)A) as we are choosing without replacement which means that the number of total parts will reduce after every pick and the probability of next pick will not be same. therefore the 2 events are not independent and the special multiplication rule applies. therefore option D is correct.
B)probability of both are defective = (7/34)*(6/33)
= 0.0374
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