ot pt 5of19 (16 complete) 3.10-T Usted below are the amounts o toconstruct a90%
ID: 3154418 • Letter: O
Question
ot pt 5of19 (16 complete) 3.10-T Usted below are the amounts o toconstruct a90% nfidence ercury (in parts per maior or pmfound in tuna sushi sa plod at dne en stores. The sample mean is 1007 p mand the savio standard dev at r erval estimate ofthe mean amount of mercury in the population 0273uetech ogy 0.99 1.01 0.95 1.42 0.56 1.04 What is the confidence interval stimate of the mean amount of mercury in the population? Round to three decimal places as needed.) Enter your answer in the edit fields and then cick Check Answer Check Anewer Clear All All parts showing s 5 3Explanation / Answer
Confidence Interval
CI = x ± t a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval
Mean(x)=1.037
Standard deviation( sd )=0.273
Sample Size(n)=7
Confidence Interval = [ 1.037 ± t a/2 ( 0.273/ Sqrt ( 7) ) ]
= [ 1.037 - 1.943 * (0.103) , 1.037 + 1.943 * (0.103) ]
= [ 0.837,1.237 ]
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