An employment information service claims the mean annual pay for full time femal
ID: 3153969 • Letter: A
Question
An employment information service claims the mean annual pay for full time female workers over age 25 and without a high school diploma is $19,100. The annual pay for a random sample of 12 full time female workers without a high school diploma provided a mean of $18,886 and a standard deviation of $1,397. Test the claim at an alpha of .05 level that the pay for non female workers without a highschool diploma is equivalent to $19,100 per year.
Accept the claim because t calculated of -0.531 is between critical t values of -2.201 and 2.201
Reject the claim because t caculated of -0.531 is greater than the critical t value of -2.201
Accept the claim because t calculated of -0.531 is less than a caculated t value of 1.796
Accept the claim because t calculated of -0.531 is between critical t values of -1.769 and 1.769
None of the above is true
a.Accept the claim because t calculated of -0.531 is between critical t values of -2.201 and 2.201
b.Reject the claim because t caculated of -0.531 is greater than the critical t value of -2.201
c.Accept the claim because t calculated of -0.531 is less than a caculated t value of 1.796
d.Accept the claim because t calculated of -0.531 is between critical t values of -1.769 and 1.769
e.None of the above is true
Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u = 19100
Ha: u =/ 19100
As we can see, this is a two tailed test.
Thus, getting the critical t,
df = n - 1 = 11
tcrit = +/- 2.20098516
Getting the test statistic, as
X = sample mean = 18886
uo = hypothesized mean = 19100
n = sample size = 12
s = standard deviation = 1397
Thus, t = (X - uo) * sqrt(n) / s = -0.530649782
As |t| < 2.201, we FAIL TO REJECT THE NULL HYPOTHESIS.
Hence, we cannot reject the claim,
OPTION A: Accept the claim because t calculated of -0.531 is between critical t values of -2.201 and 2.201. [ANSWER]
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