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2. Collette is self-employed, selling items at Home Interior parties. She wants

ID: 3153663 • Letter: 2

Question

2. Collette is self-employed, selling items at Home Interior parties. She wants to estimate the average amount a client spends at each party. A random sample of 35 clients' receipts gave a sample mean of $34.70 and historically we know the population standard deviation of spending at these parties to be $4.85. a.Explain why you may assume your data is normally distributed. b.Find a 90% confidence interval for the average amount expected to be spent by a given client at a party. c.Write a brief explanation of the meaning of the confidence interval in the context of this problem d. For a party with 35 clients, use part (b) to estimate a range of dollar values for Collette's total sales at that party.

Explanation / Answer

a.Explain why you may assume your data is normally distributed.

The sample size is large enough, n = 35, and we know the population standard deviation, so central limit theorem would lead us that the sample means are normally distributed.

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b.Find a 90% confidence interval for the average amount expected to be spent by a given client at a party.

Note that              
Margin of Error E = z(alpha/2) * s / sqrt(n)              
Lower Bound = X - z(alpha/2) * s / sqrt(n)              
Upper Bound = X + z(alpha/2) * s / sqrt(n)              
              
where              
alpha/2 = (1 - confidence level)/2 =    0.05          
X = sample mean =    34.7          
z(alpha/2) = critical z for the confidence interval =    1.644853627          
s = sample standard deviation =    4.85          
n = sample size =    35          
              
Thus,              
Margin of Error E =    1.34845039          
Lower bound =    33.35154961          
Upper bound =    36.04845039          
              
Thus, the confidence interval is              
              
(   33.35154961   ,   36.04845039   ) [ANSWER]

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c.Write a brief explanation of the meaning of the confidence interval in the context of this problem

Hence, we are 90% confident that the true mean amount a client spends at each party is between $33.35154961   and $36.04845039. [ANSWER]

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d. For a party with 35 clients, use part (b) to estimate a range of dollar values for Collette's total sales at that party.

We then multiply this confidence interval by 35, so we have

(   33.35154961*35   ,   36.04845039*35   )   

= ($1167.304236   , $1261.695764) [ANSWER]