studied statisties would understand. (2 pts) li f the lision problem-a about the
ID: 3153353 • Letter: S
Question
studied statisties would understand. (2 pts) li f the lision problem-a about the null hypothesis. Write a eCK conclusion that a person who has never 28. A motorist claims that the Mauldin police issue an average of 6o speeding day. The following show the number of speeding tickets issued ach day eo one month. Assume that standard deviation is 12. Is there enough evidence to motorist's claim if ao.o5? 72 45 36 68 6 57 60 83 26 ofso sp-dngikes of 6o speeding ticketdign ay for a period of to reject the 5887 48 59 6 56 64 68 42 57 57 63 49 73 75 42 63 64 60 57 6o 83 26 60 72 29. For each situation, gi would reject o faoSiven the value for alpha and the value for p, determine if you would reject or fail to reject the null hypothesis +005 and posse Tne Level d, -0.025 and p-0.036 c, -0.01 and p-0.09 Hypothesis testing 30. Decision Rule Based on P-value To use a P-value to make a conclusion in a hypothesis test, compare the P-value to a. IfPsa, then reject Ho If P > a, then fail to reject Ho 31. In a recent survey, the average amount of money students have in their pockets is $5-40 with a standard deviation of $1.20. A teacher feels that the average amount is actually higher. She surveys So randomly selected students and finds the average amount is $5.50. At -005, test the teacher's claim that the average amount of money is actually higher than $5-40. 32. Given Ho = 150, Ha-150, and P-0.0390 (a) Do you reject or fail to reject Ho at the o.or level of significance? b) Do you reject or fail to reject He at the o.os level of significance?Explanation / Answer
33) H0= U= 300
HA = U<300
AS N = 40 WE WILL DO IT BY Z TEST
AS ALPHA = 0.05, IT IS A LEFT TAIL TEST
THE REJECTION REGION = Z<-1.96
Z = (X-MEAN)(STANDARD DEVIATION/SQRT(N))
Z = (290 - 300)/(22/SQRT(40))
Z = -2.88
THEREFORE AS Z = -2.88<-1.96
THEREFORE WE WILL REJECT THE NULL HYPOTHESIS.
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