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The \"fear of negative evaluation \" (FNE) scores for 11 female students known t

ID: 3152858 • Letter: T

Question

The "fear of negative evaluation " (FNE) scores for 11 female students known to suffer from the eating disorder bulimia and 14 female students with normal eating habits are represented in the table below. (The higher the score, the greater is the fear of a negative evaluation.) Complete parts a and b below. Click here to view the table. Find a 95% confidence interval for the difference between the population means of the FNE scores for bulimic and normal female students. Interpret the result. The 95% confidence interval is (Round to two decimal places as needed.) Interpret the result. Choose the correct interpretation below. We are 95% confident that the difference in mean FNE scores for bulimic and normal students is outside the confidence interval. We are 5% confident that the difference in mean FNE scores for bulimic and normal students is inside the confidence interval. We are 5% confident that the difference in mean FNE scores for bulimic and normal students is outside the confidence interval. We are 95% confident that the difference in mean FNE scores for bulimic and normal students is inside the confidence interval.

Explanation / Answer

a.
CI = x1 - x2 ± Z a/2 * Sqrt ( sd1 ^2 / n1 + sd2 ^2 /n2 )
Where,
x1 = Mean of Sample 1, x2 = Mean of sample2
sd1 = SD of Sample 1, sd2 = SD of sample2
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x1)=13.8182
Standard deviation( sd1 )=4.9157
Sample Size(n1)=11
Mean(x2)=13.1429
Standard deviation( sd2 )=5.2894
Sample Size(n12=14
CI = [ ( 13.8182-13.1429) ±Z a/2 * Sqrt( 24.16410649/11+27.97775236/14)]
= [ (0.68) ± Z a/2 * Sqrt( 4.2) ]
= [ (0.68) ± 1.96 * Sqrt( 4.2) ]
= [-3.34 , 4.69]

b.
W arc 95% confident that the difference in mean FNE scores for bulimic and normal students is
inside the confidence interval.

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