This is the 2nd time I\'m submitting this question . I only need the answer for(

Question

This is the 2nd time I'm submitting this question. I only need the answer for(C)and the answer is a simplified fraction.

Assume that a company hires employees on Mondays ,Tuesdays, Wednesdays with equal likelihood. Complete parts (a) through (c) below. If two different employees are randomly selected, what is the probability that they were both hired on a Wednesday? (A) & (B) are already answered.

A)The probability is__1/9______ (Type an integer or a simplified fraction.) B) If two different employees are randomly selected, what is the probability that they were both hired on the same day of the weekday of the week? The probability is__1/3_____(Type an integer or a simplified fraction.)

What is the probability that 66 people in the same department were all hired on the same day of the weekday of the week? Is such an event unlikely? The probability is______ (a simplified fraction.)

Explanation / Answer

answer c) probaility of hiring on mondays =1/3

probaility of hiring on tuesdays =1/3

probaility of hiring on weddays =p=1/3

out of n=66 , let x people hired on monday , therefore x will be binomial random variable with parameter n=66 and p=1/3

P(X=x)=nCxpx(1-p)n-x

P(X=66)=66C66(1/3)66(1-1/3)66-66=(1/3)66

proabability of 66 people hired on mondays=(1/3)66

proabability of 66 people hired on tuesday=(1/3)66

proabability of 66 people hired on wednesdays=(1/3)66

proabability of 66 people hired on same day =(1/3)66 + (1/3)66 +(1/3)66 =3*(1/3)66 =(1/3)65

this is almost zero and such an event is not likely i.e event is unlikely

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