Section (Please circle:) 020D 8:00 Tuesday for lecture section 010 030D 8:00 Tue

Question

Section (Please circle:) 020D 8:00 Tuesday for lecture section 010 030D 8:00 Tuesday for lecture section 011 02ID 9:30 Tuesday for lecture section 010 031D 9:30 Tuesday for lecture section 011 022D 8:00 Thursday for lecture section 010 032D 8:00 Thursday for lecture section 011 023D 9:30 Thursday for lecture section 010 033D 9:30 Thursday for lecture section 011 A fair die is rolled three times; Y is the sum of the three numbers obtained. Find the probability that y = 6. (I suggest using a tree diagram.)

Explanation / Answer

Hi.

You can find the probability using this way

P=(pro case)/cases

so, if you rolled the die 3 times and you want to know what is the probability to sum 6. You have only those cases.

(first roll, second roll, third roll)

if
(1,2,3)
(4,1,1)
(2,2,2)

if you dont care about the order of the numbers you must multiplicate for *6

(1/6)(1/6)(1/6)*6=0,0277

the probability is 0,0277

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