Lester Hollar is vice president for human resources for a large manufacturing co
ID: 3152432 • Letter: L
Question
Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results.
Employee - Before - After
1 - 6 - 5
2 - 6 - 2
3 - 7 - 1
4 - 7 - 3
5 - 4 -3
6 - 3 - 6
7 - 5 - 3
8 - 6 - 7
At the .05 significance level, can he conclude that the number of absences has declined? Estimate the p-value. Hint: For the calculations, assume the "Before" data as the first sample.
1. Reject H0 if t > . (Round your answer to 3 decimal places.)
2. The test statistic is . (Round your answer to 3 decimal places.)
Explanation / Answer
Lester Hollar is vice president for human resources for a large manufacturing company. In recent years, he has noticed an increase in absenteeism that he thinks is related to the general health of the employees. Four years ago, in an attempt to improve the situation, he began a fitness program in which employees exercise during their lunch hour. To evaluate the program, he selected a random sample of eight participants and found the number of days each was absent in the six months before the exercise program began and in the six months following the exercise program. Below are the results.
Employee - Before - After
1 - 6 - 5
2 - 6 - 2
3 - 7 - 1
4 - 7 - 3
5 - 4 -3
6 - 3 - 6
7 - 5 - 3
8 - 6 - 7
At the .05 significance level, can he conclude that the number of absences has declined? Estimate the p-value. Hint: For the calculations, assume the "Before" data as the first sample.
1. Reject H0 if t > 1.895 . (Round your answer to 3 decimal places.)
2. The test statistic is 1.698. (Round your answer to 3 decimal places.)
Calculated t=1.698 < 1.895, the table value.
The null hypothesis is not rejected.
There is not enough evidence to conclude that the number of absences has declined.
t = d/( s/sqrt(n))
Paired t Test is used
Upper tail test
Data
Hypothesized Mean Difference
0
Level of significance
0.05
Intermediate Calculations
Sample Size
8
DBar
1.7500
Degrees of Freedom
7
SD
2.9155
Standard Error
1.0308
t Test Statistic
1.6977
Upper-Tail Test
Upper Critical Value
1.8946
p-Value
0.0667
Do not reject the null hypothesis
Paired t Test is used
Upper tail test
Data
Hypothesized Mean Difference
0
Level of significance
0.05
Intermediate Calculations
Sample Size
8
DBar
1.7500
Degrees of Freedom
7
SD
2.9155
Standard Error
1.0308
t Test Statistic
1.6977
Upper-Tail Test
Upper Critical Value
1.8946
p-Value
0.0667
Do not reject the null hypothesis
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