A study in Pittsburgh measured various cardiovascular risk factors in children a
ID: 3151956 • Letter: A
Question
A study in Pittsburgh measured various cardiovascular risk factors in children at birth and during their first 5 years of life. In particular, heart rate was assessed at birth, 5 months, 15 months, 24 months, and annually thereafter until 5 years of age. Heart rate was related to age, sex, race, and socioeconomic status. The data in Table 3 were presented relating heart rate to race among newborns
Table 3. Mean heart rate for white and black groups.
Determine whether there is a significant difference in mean heart rate between Caucasian and African- American newborns (=0.05). Report a p-value for two-sided alternative).
Race Mean Heart Rate (bpm) Standard Deviation (bpm) Sample White 125 11 218 Black 133 12 156Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u1 - u2 = 0
Ha: u1 - u2 =/ 0
At level of significance = 0.05
As we can see, this is a two tailed test.
Calculating the means of each group,
X1 = 125
X2 = 133
Calculating the standard deviations of each group,
s1 = 11
s2 = 12
Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):
n1 = sample size of group 1 = 218
n2 = sample size of group 2 = 156
Thus, df = n1 + n2 - 2 = 372
Also, sD = 1.215780735
Thus, the t statistic will be
t = [X1 - X2 - uD]/sD = -6.580133878
where uD = hypothesized difference = 0
Now, the critical value for t is
tcrit = +/- 1.966361504
Also, using p values,
p = 1.59913*106-10 [ANSWER, P VALUE]
As |t| > 1.966, and P < 0.05, WE REJECT THE NULL HYPOTHESIS.
Hence, there is a significant difference in mean heart rate between Caucasian and African- American newborns at 0.05 level. [CONCLUSION]
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