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A chemical engineer is investigating the effect of process operating temperature

ID: 3151210 • Letter: A

Question

A chemical engineer is investigating the effect of process operating temperature on product yield. The study results in the data given below; use your knowledge of least squares regression to construct a linear model for predicting yield from temperature.

a) The mean of Temperature is in the range:

60-70

70-80

80-90

90-100

100-110

110-120

120-130

130-140

140-150

150-160

b) The mean of Yield is in the range:

60-70

70-80

80-90

90-100

100-110

110-120

120-130

130-140

140-150

150-160

c) The standard deviation of Yield is in the range:

0-5

5-10

10-15

15-20

20-25

25-30

d) The intercept of the fitted regression line is closest to:

9.40

2.03

0.473

-1.87

e) The slope of the fitted regression line is closest to:

9.40

2.03

0.473

-1.87

f) The yield predicted by the regression model for a temperature of 150 degrees is closest to:

65.435

74.596

72.520

69.075

73.803

g) The residual error for a temperature of 150 degrees is closest to:

+0.03

-5.52

+5.52

-0.11

+0.11

h) If the yield were measured in ounces instead of grams (note that 1 gram is 0.35274 ounces), the slope would change by a factor of:

0.35274

1/0.35274

would not change

None of the above.

i) If the yield were measured in ounces instead of grams (note that 1 gram is 0.35274 ounces), the correlation coefficient would increase by a factor of:

0.35274

1/0.35274

would not change

None of the above.

a.

60-70

b.

70-80

c.

80-90

d.

90-100

e.

100-110

f.

110-120

g.

120-130

h.

130-140

i.

140-150

j.

150-160

Explanation / Answer

From Excel

a) Mean Temp range is 140-150

b) Mean yield Range is 60-70

c)standard dev range for Yield is 10-15

d) From Excel

Intercept= -1.7097

e) Slope =0.4715

Temp Yield 100 43.6215 110 46.6231 120 58.2752 130 58.8906 140 65.4354 150 74.596 160 72.5202 171 79.0639 180 83.628 190 84.4351 Means= 145.1 66.7089 stds= 30.36976 14.6038
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