A television sports commentator wants to estimate the proportion of citizens who

Question

A television sports commentator wants to estimate the proportion of citizens who "follow professional football". Complete parts (a) through (c). What sample size should be obtained if he wants to be within 4 percentage points with 96 percentage confidence if he uses an estimate of 48 percentage obtained from a poll? The sample size is 658. (Round up to the nearest integer.) What sample size should be obtained if he wants to be within 4 percentage points with 96 percentage confidence if he does not use any prior estimates? The sample size is L (Round up to the nearest integer.)

Explanation / Answer

Compute Sample Size ( n ) = n=(Z/E)^2*p*(1-p)
Z a/2 at 0.04 is = 2.054
Sample Proportion = 0.5
ME = 0.04
n = ( 2.054 / 0.04 )^2 * 0.5*0.5
= 659.206 ~ 660

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