with solution too please Saimpie Poo... Saliipie pOu.. Sample Pooled Variances t
ID: 3150577 • Letter: W
Question
with solution too please
Explanation / Answer
Step 1:
Formulating the null and alternative hypotheses,
Ho: u1 - u2 = 0
Ha: u1 - u2 =/ 0 [ANSWER]
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Step 2:
Here, we use the t distribution.
df = n1 + n2 - 2 = 51 [ANSWER]
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Step 3:
At level of significance = 0.05
As we can see, this is a two tailed test.
Getting the critical value using table/technology,
tcrit = +/- 2.00758377 [ANSWER, CRITICAL VALUE]
Hence, we reject Ho when |t| > 2.008. [ANSWER]
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STEP 4:
Calculating the means of each group,
X1 = 0.84
X2 = 1.68
Calculating the standard deviations of each group,
s1 = 0.68
s2 = 1.37
Thus, the pooled standard deviation is given by
S = sqrt[((n1 - 1)s1^2 + (n2 - 1)(s2^2))/(n1 + n2 - 2)]
As n1 = 13 , n2 = 40
Then
S = 1.242608736
Thus, the standard error of the difference is
Sd = S sqrt (1/n1 + 1/n2) = 0.396707732
As ud = the hypothesized difference between means = 0 , then
t = [X1 - X2 - ud]/Sd = -2.117427848 [ANSWER, TEST STATISTIC]
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As |t| > 2.008, we REJECT THE NULL HYPOTHESIS.
Hence, there is significant differnce between the mean number of police officers per 1000 residents in Urban and Non-urban jurisdictions. [CONCLUSION]
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Hi! If you use another method/formula in calculating the degrees of freedom in this t-test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!
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