The reading speend second grade students is approximately normal, with a mean of
ID: 3150239 • Letter: T
Question
The reading speend second grade students is approximately normal, with a mean of 90 words per minute (wpm) and a standard deviation of 10 wpm. Complete parts (a) C. Increasing the sample size increases the probability because sigma decreases as n increases increasing the sample size oecreases the probability because sigma_x increases as n increases. (e) A teacher instituted a new reading program at school After 10 weeks in the program, it was found that the mean reading speed of a random sample of 20 second qr.ide students was 92 1 wpm. What might you conclude based on this result? Select the correct choice and M m the answer box in your choice below.Explanation / Answer
MEAN = 90
STANDARD DEVIATION = 10
E) WE NEED TO FIND THE PROBABILITY OF EXCEEDING 92.1
AS THE IDTRIBUTIO IS NORMAL WE WILL USE
Z = (X-MEAN)/STANDARD DEVIATION
THEREFORE P(X>92.1) =
) For x = 92.1, z = (92.1 - 90) / 10 = 0.21
Hence P(x > 92.1) = P(z > 0.21) = [total area] - [area to the left of 0.21]
1 - [area to the left of 0.21]
now from the z table we will take the value of z score = 0.21
= 1 - 0.5832 = 0.4168
THEREFORE OPTION A WITH PROBABILITY 0.4168 IS CORRECT
F) HERE WE WILL USE THE FORMULA =
X = MEAN + ZSCORE* STANDARD DEVIATION
AS THE PROBABILITY GIVEN = 5% = 0.05
WE WILL GET THE Z SCORE FOR 0.05 FROM THE Z TABLE WHICH COMES OUT TO BE = -1.645
THEREFORE X = 90 -1.645*10 = 73.55
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