A problem is given below. Instead of trying to solve that problem, state a simpl

Question

A problem is given below. Instead of trying to solve that problem, state a simpler problem and solve it instead. Using all the letters of the alphabet, how many two-letter codes can we form if we are allowed to use the same letter more than once? (Note: bg is different from gb.) Which of the following is a simpler version of the given problem? O A. Using four of the letters of the alphabet, how many two-letter codes can we form if we are not allowed to use the same letter more than once? O B. Using four of the letters of the alphabet, how many two-letter codes can we form if we are allowed to use the same letter more than once? O C. In how many ways can all the letters of the alphabet be arranged? O D. Using all the letters of the alphabet, how many two-letter codes can we form if we are not allowed to use the same letter more than once? What is the solution to this simpler problem?

Explanation / Answer

Option B

(Only A ,B are simpler version

In A same alphabet is not allowed to use more than once )

Solution to simpler version

No of alphabet =4

No of two letter codes = 4c1 ×4c1 = 4×4=16

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