Resource allocation. A coffee manufacturer uses Colombian and Brazilian coffee b
ID: 3144570 • Letter: R
Question
Resource allocation. A coffee manufacturer uses Colombian and Brazilian coffee beans to produce two blends, robust and mild. A pound of the robust blend requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans. A pound of the mild blend requires 6 ounces of Colombian beans and 10 ounces of Brazilian beans. Coffee is shipped in 125pound burlap bags. The company has 40 bags of Colombian beans and 37 bags of Brazilian beans on hand. How many pounds of each blend should they produce in order to use all the available beans?
Robustequals = lbs
Mildequals= lbs
(Round each answer to the nearest pound.)
Explanation / Answer
Given data:
There are two types of coffee beans Colombian and Brazilian which are used to produce two blends called robust and mild.
One pound(1lb) of the robust blend requires 12 ounces of Colombian beans and 4 ounces of Brazilian beans.
similarly, one pound(1lb) of the mild blend requires 6 ounces of Colombian beans and 10 ounces of Brazilian beans.
one bag size is 125 pounds(lbs) and company has 40 bags of Colombian beans and 37 bags of Brazilian beans.
procedure:
As one pound = 16 ounce
one bag size = 125*(16 ounce) = 2000 ounce
That implies,
Size of 40 bags of Colombian beans = 40*(2000 ounce) = 80000 ounce
Size of 37 bags of Brazilian beans = 37*(2000 ounce) = 74000 ounce
Assume there are 'R' pounds(lbs) of Robust blend and 'M' pounds(lbs) of Mild blend
As one pound of robust blend requires 12 ounces of Colombian beans and one pound of mild blend requires 6 ounce of Colombian beans,
The equation should be
12*R+6*M=80000 -------(1)
similarly for Brazilian beans, the equation is
4*R+10*M=74000 --------(2)
multiply equation (2) with constant 3 =>
12*R+30*M=222000 -------(3)
subtract (1) from (3)
we get, 24*M=142000 => M = (17750/3) = 5916.667
Now, substitute M= (17750/3) in (1)
=> R = (11125/3) = 3708.333
Finally, answer is
Robustequals= 5917 lbs
Mildequals= 3708 lbs
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