Find the area of sector AOB with radius 12 fort and mAOB = 280 degree. Give your

Question

Find the area of sector AOB with radius 12 fort and mAOB = 280 degree. Give your answer in terms of pi Find the perimeter of the triangle shown below. Give your answer in simplified radical form. Mary is painting the flow of a gazebo that is in the shape of a regular hexagon with 8-foot side lengths. What the total area that must be painted? Ron is building a silo with the measurements shown. a. Find the surface area of the silo, excluding the floor, to the nearest whole meter. Use 3.14 for pi. Show your work. b. Find the volume of the silo to the nearest whole meter. Use 3.14 for pi. Show your work.

Explanation / Answer

Q.45 Angle AOB in terms of is = (280/360) 2 = 14/9

Area of the sector is = * (12)2 * (14/9) /2 = 112 feet2

Q.46 Here x = 15 tan 300 = 15/3

and y = 15/ cos 300 = 30/3

so perimeter of triangle = 15 + 15/3 + 30/3 = 15 (1 + 3) feet

Q.47 The area of an regular hexagonal when the length of one side is a = 33/2 a2

so area A = 33/2 * 82 = 166.28 feet2

Q.48 a. Now there are two areas here

(a) The circular cyliderical area which is equals to 2 rh

(B) the upper surface area as it has to exclude the base area = r2

where r is the diameter of the cylinder = 33/2 = 16.5 metre and h is the height = 50 metre

so total area =  2 rh +   r2 = 2 * 3.14 * 16.5 * 50 + 3.14 * 16.5 * 16.5 = 6036 metre2

(b) VOlume of the silo V = r2 h = 3.14 * 16.5 * 16.5 * 50 = 42743 metre3

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