If you add 0.2 mL of 10^-4M ACh to 20 mL Tyrode\'s buffer, then the [ACh] is now

Question

If you add 0.2 mL of 10^-4M ACh to 20 mL Tyrode's buffer, then the [ACh] is now =___ If you now add another 0.2 mL of 10^-4M ACh to the same 20mL of Tyrodes', then the [ACh] is now =___ If you add 0.4mL of an ACh stock solution to 20 mL of Tyrode's and found that you now have a final [ACh] of 2 times 10^-6M in Tyrode's, what was the [ACh] in the original stock solution?___ Calculate the following if initial bath volume in 20 mL: Add 0.2 mL of 10^-6M ACh to bath yields [ACh] in the bath:___ Add 0.2 mL of 10^-5M ACh to bath yields [ACh] in the bath:___ Add 0.2 mL of 10^-4M ACh to bath yields [ACh] in the bath:___ Add 0.2 mL of 10^-3M ACh to bath yields [ACh] in the bath:___

Explanation / Answer

2) C1XV1=C2XV2

where C1-concentration of first solution

C2-concentration of second solution

V1- volume of first solution

V2- volume of second solution

a)0.2*10^-4 = 20 *[ACH]

[ACH]= 1x10^-6 M

b)0.4*10^-4 =20*[ACH]

[ACH]=2x10^-6 M

3)V1*C1=V2*C2

0.4*x=20*2*10^-6

x=[ACH]=1x10^-4

4)

a)0.2*10^-6=[ACH]*20

[ACH]=1x10^-8

b)0.2*10^-5=[ACH]*20

[ACH]=1x10-7

c)0.2*10^-4=[ACH]*20

[ACH]=1X10^-6

D)0.2*10^-3=[ACH]*20

[ACH]=1x10^-5

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