A survey was taken of randomly selected Americana, age 65 and older, which found

Question

A survey was taken of randomly selected Americana, age 65 and older, which found that 411 of 1014 men and 542 of 1069 women suffered from some form of arthritis. a) Create a 95% confidence interval for the difference in the proportions of senior men and women who have this disease. b) Interpret your interval in this context. c) Does this suggest that arthritis is more likely to afflict women than men? Explain. (Round to one decimal place as needed.) c) Does this suggest that arthritis is more likely to afflict women than men? Select the correct answer below and, if necessary, fill in the answer boxes within your choice. A. No, a conclusion cannot be made based on the confidence interval. B. Yes, the entire interval lies above 0. C. Yes, there is 95% confidence, based on these samples, that about % of senior women suffer from arthritis, while only % of senior men suffer from arthritis. (Round to one decimal place as needed.) D. No, the interval is too dose to 0. a) Let p, be the sample proportion of senior women suffering from some form of arthritis, and let P2 be the sample proportion of senior men suffering from some form of arthntis Create a 95% confidence interval for the difference in the proportions of senior men and women who have this diseaso. - p? The confidence interval is (DO-(Round to three decimal places as needed.) b) There is 95% confidence, based on these samples, that the proportion of American worn on. age 65 and older, who suffer from arthntis is between % and j)% ? than the proportion of American men of the same age who suffer from arthritis.

Explanation / Answer

Test and CI for Two Proportions

Method

Descriptive Statistics

Estimation for Difference

CI based on normal approximation

Test

a) 95% confidence interval -   

p: proportion where Sample 1 = Event p: proportion where Sample 2 = Event Difference: p - p

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