Just from 11 to 21. u! kin-ky a) true ,b) false . n! R= (n-ky.\" a) true ,b) fal
ID: 3142871 • Letter: J
Question
Just from 11 to 21. u! kin-ky a) true ,b) false . n! R= (n-ky." a) true ,b) false 3. The Binomial Theorem says (a + b)" .0( )ak bn-k. a) true ,b) false 4. 2. ) = 2n , a) true ,b) false 5.+-0. a) true,b) false 6. The number of permutations of ABBA is a) 2 ,b) 4 ,c) 6 d) 8 ,e) none of these 7.(-18. a) true,b) false 8. The number of permutations of AAABBC is a) 20,b)40,c) 60,d) 80,e) none of these 9. Toss a pair of dice. P(sum-7) a) 1/36,b) 4/36,c) 6/36,d) 9/36,e) none of these 10. Toss a pair of dice. P(sum 12) a) 1/36,b)4/36,c) 6/36,d) 9/36,e) none of these 11. LetX and Y be the results of two die tosses. P(X Y)·a) 1/36,b) 4/36,c) 6/36,d) 9/36-e) none of these 12. Let X and Y be the results of two die tosses. Plx-Y|s 1)-a) 10/36,b) 11/36,c) 12/36,d) 13/36,e) none of these 13. Let X and Y be the results of two die tosses. PUX-Yl·5)-a) 1/36·b)2/36,c) 3/36,d) 4/36,e) none of these 5·(i)-G)-()-G)+(t)-0 a) true . b) false 14. (i)-("ii)-(:). a) true ,b) false -1) a) true,b) false 15. Suppose an urn contains R·6 red and B-4 blue marbles. If n·5 marbles are drawn w/o replacement, and X is the number of red marbles in the sample, then P(X 3) a) 16/42,b) 20/42,c) 23/42,d) 26/42,e) none of these 16. In 15., P(X-5) a) 1/42 ,b) 3/42 ,c) 5/42,d) 7/42 ,e) none of these 17. Suppose Fred Meyer has 6 bananas and 3 apples. In how many ways can we buy 2 bananas and 1 apple? a) 25 35 , c) 45 ,d) 55,e) none of these 18. If a sample of Bass weigh { 1,2,3,4,5) lbs, the sample mean is a) 1 ,b) 2-c) 3·d) 4 ,e) none of these 19. If a sample of Bass weigh (1,2,3,4.5) lbs, the sample variance is a) 10/4 b) 20/4 c) 30/4,d) 40/4,e) none of these 20. If a sample of Bass weigh {1,2,3,4,5) lbs, the sample median is a) 1 ,b)2 3,d) 4 ,e) none of these 21. Statistics is based on Probability. a) true,b) false 22. If X is a rv and P(X=x)sL for 0 n, then X is a Binomial n. a)true,b) false x
Explanation / Answer
11) There are 6 cases where x=y and the total number of outcomes is 6*6=36
So, the probability, P(x=y)=6/36
So, the correct option is (c) 6/36
12) The difference of two dice is 1 in the following cases 1-2, 2-3, 3-4, 4-5, 5-6
So, there are total 10 cases and the total outcome is 36
So, the probability P(|x-y|=1)=10/36
The correct option is (a) 10/36
13) The difference is 5 for the cases 1-6 or 6-1. That is, two cases are possible.
So, the probability P(|x-y|=5)=2/36
Correct option is (b)2/36
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