Size of Earth and Moon Lab Report Form (Attach additional paper if you need extr

Question

Size of Earth and Moon Lab Report Form (Attach additional paper if you need extra room for calculations and or explanations) Class/Section Size of the Earth: UALR latitude as a decimal number 34.02 de 34o Aq' los" (Show calculation.) ko.S 34.82 or 3A.81g50333. Intersection of -40 and I-430 latitude as a decimal number: 34.82. deg 34e Aa'ege ot.2. (Show calculation 34.02. 34.81894444 Intersection of I-40 and I-430 latitude minus UALR latitude: (Show calculation.) oooo 388A Circumference of Earth (round to nearest km) km (Show calculation.) and then (Explain clearly in words the concepts behind the km calculation) lkm. uo.ept 122 mi See attached the total Radius of the Earth (round to nearest km): (Show calculation) c ?r. d 303833 km 3-14 d 101 Percent error (Express as a percentage, one decimal place) (Show calculation.) Up 371 Revised: 05h15l 2017

Explanation / Answer

Angles that you found in degree are correct.

angle difference between both locations =(34 degrees 49minutes and 10.5 seconds)-(34 degrees 49 minutes and 8.2 seconds)=2.3 seconds= 2.3/3600 degree= 0.000638888888889 degree

you haven't clearly mentioned about what is the distance between both locations so i'm assuming that is (x km)
Now we just setup simple ratio to find the circumference of earth

(circumference)/(angle)=(arc length)/(angle)
(circumference)/(360 degree)=(x km)/(0.000638888888889 degree)
circumference =(x km)/(0.000638888888889 degree)*(360 degree)
circumference =563478.26087x km
Now you can plug value of x (given or calculated distance between two locations) to find the approx perimeter.

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