?https://www.mathxl.com/Sudent/p ework.aspx?homeworkld-4647 Math 1118-91 Dalke S

Question

?https://www.mathxl.com/Sudent/p ework.aspx?homeworkld-4647 Math 1118-91 Dalke S18 Homework: Homework 7 (3.3 4) Score: 0 of 1 pt 3.4.21 The figure shows the graph of y ax bx+c. Suppose that the points (-h.yo) (0%) , and (hy2) are on the graph. The area enclosed by the parabola, the x-axis, and the lines x =-h and x= h may be given by the following formula. (o.yi) Area 3 (Yo +41y2) e area enclosed by f(x)=-6x2 + 8, the x-axis, and the lines x--1 and X: 1. The area is (Type an integer or a fraction.) Enter your answer in the answer box and then click Check Answer All parts showing O Type here to search

Explanation / Answer

f(X) = - 6x^2 + 8

x = -1 and x = 1

h = 1

y1 = 8

the graph passes through ( -1 , 2) and ( 1, 2)

yo = 2 , y2 = 2

plugging the values in the formula

area = 1/3 [ 2 + 4*8 + 2 ]

area = 12

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