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Firefox File Edit View History Bookmarks Tools Window Help ? ?? Thu 2:19 PM 100e,?. Login × Chapters 11&12-Interview × + Chttps:/www.webassign.net/web/Student/Assignment-Responses/sQ Search Most Visited B Boise State llack Board H Neeflix Google Pinterest YouTube Dish Anywhere Facebook 0/1 points 1 Previous Answers CraudCL2 6.2.006. My Notes O Ask Your Teach In a study of 500 men, diastolic blood pressure was found to be approximately normally distributed, with a mean of 82 millmeters (mm) of mercury and standard deviation of 10 milimeters Use the 68-95-99.7% rule to determine what percentage of the test group had a diastolic pressure between 62 millimeters and 102 millimeters of mercury eBook Submit Answer Save Progress Practice Another Version My Noces Ask Your Teacher It is found that the number of raisins in a box of a popular cereal is normally distributed, with a mean of 133 raisins per box and a standard deviation of 10 raisins. My cereal box has 147 raisins. What is the z-score for this box of cereal? Round your answer to one decimal place. elook My Notes Ask Your dish

Explanation / Answer

mean is 82 mm
standard deviation is 10 mm

We are to find the percentage of the test group with diastolic pressure between 62 mm and 102 mm;
On the z-scale, 62 mm = 62-82 / 10 = -20/10 = -2
and on the z-scale 102 mm is = 102 - 82 / 10 = 20/10 = 2

Thus, we are to find the % of values that lie between -2 and + 2 on the standard normal curve;
as per the 68-95-99.7% rule


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Mean of raisins = 133 and standard deviation = 10 mm
formula for z score of value x = (x- mean) / std dev
so for x= 147, its z score will be = (147-133) / 10 = 14/10 = 1.4;
Thus, z-score of 147 raisins would be = 1.4;

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