20. The value of (3 to 2 5 power) square is equal to A 453 8 253 D 362 A 2A-2x 2
ID: 3136660 • Letter: 2
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20. The value of (3 to 2 5 power) square is equal to A 453 8 253 D 362 A 2A-2x 21 Give the factors of ax D 2x-2a 22 Given (arXa) 100,000. Find a A. 5 8 10 C 11 23 CE BOARD NOV 2002 Find the value of x in (3*5)(9*6)-3(2x) Note: the expression A means power A 85 B 10 4 5 24. CE BOARD MAY 2003 If log, 12 2.262, find the value of log 3 A. 0.75 B. 2 C. 0.55 D. 1.00 25 CE BOARD MAY 2004 If log 6 1.2925, find the value of log 11. A. 1.66 D. 1.55 26. CE BOARD NOV. 2005 If log 146 5, find log ox A 2.6392 B. 0.4329 C. 0.7562 D. 1.2829 27. CE BOARD NOV 2007 The logarithm of the product and quotient of two numbers are 147712125 and-007918125, respectively. What is the smallerExplanation / Answer
20) (3 to 2.5 power) square = (32.5)2 = 32.5*2 = 35 = 243
Therefore, the value of (3 to 2.5 power) square is equal to 243.
21) Given expression is a2-x2.
Now, a2-x2 = (a+x)(a-x)
Therefore, the factors of a2-x2 are (a+x) and (a-x).
22) (a2)(a3) = 100000
i.e., a2+3 = 100000
i.e., a5 = 105
i.e., a = 10
Therefore, the value of a is 10.
23) (3^5)(9^6) = (3^2x)
i.e., 35*96 = 32x
i.e., 35*(32)6 = 32x
i.e., 35*32*6 = 32x
i.e., 35+12 = 32x
i.e., 317 = 32x
i.e., 2x = 17
i.e., x = 17/2
i.e., x = 8.5
Therefore, the value of x is 8.5
24) Given, logx12 = 2.262
i.e., (log 12)/(log x) = 2.262
i.e., log x = (log 12)/2.262
i.e., (log 3)/(log x) = (log 3)*(2.262)/(log 12)
i.e., logx3 = 1.000
Therefore, the value of logx3 is 1.000
25) Given, logx6 = 1.2925
Now, logx11 = (logx6)*(log 11)/(log 6)
i.e., logx11 = (1.2925)*(log 11)/(log 6)
i.e., logx11 = 1.73
Therefore, the value of logx11 is 1.73
26) Given, logx146 = 5
Now, log10x = (log 146)/[(log 10)*(logx146)]
i.e., log10x = (log 146)/[(log 10)*5]
i.e., log10x = 0.4329
Therefore, the value of log10x is 0.4329
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