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Question

Do rHomeworkaspx/hom rkld 473661279&questionld; 2&flushed-false;&cld; 4930778&centerwinay; MATH110 K009 Win 18 Edwina Watson& 1 3/10118 11:14 A Homework: Week 5: Homework 4.3 Score: 0 of 1 pt 13or14 (13 complete) 1 > HW Score: 73 33%, 11 of 15 *4.3.17 Assigned Media i Question Help One canned juice drink is 30% orange juice, another is 10% orange juice How many Bers of each should be mixed together in order to get 20L that is 23% orange juice? How many liters of the 30% orange juice should be in the mixture?

Explanation / Answer

Let x liters of 30 % orange juice be mixed with y liters of 10 % orange juice to get 20 liters of 23 % orange juice. Then x+y = 20…(1) and 0.3x +0.1y = 0.23*20 = 4.6 or, 3x+y = 46…(2).

From the 1st equation, we get y = 20-x. On substituting this value of y in the 2nd equation, we get 3x+20-x = 46 or, 2x = 46-20 or, 2x = 26 so that x = 26/2 = 13. Then y = 20-13 = 7. Thus, 13 liters of 30 % orange juice has to be mixed (with 7 liters of 10 % orange juice to get 20 liters of 23 % orange juice).

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