Scan this code to link to section lecturevideos. 4 16. f(x) = (x2-1)2 18. f(x) 3

Question

Scan this code to link to section lecturevideos. 4 16. f(x) = (x2-1)2 18. f(x) 3x .15. f(x) = (x-5)2 17. f(x)r Find the x-intercepts and discuss the behavior of t polynomial finction at its x-intercepts 19. f(x) = (x-4)2 21. f(x) = (2-1)3 23, f(x) = 4x-1 25.f(x) = x2-3x+10 26. f(x) =x4-16 27, f(x) = x3-3x2 29, f(x) = 2x3-5x2 + 4x-1 30. f(x) = x3-k2 + 4 31, f(x) =-2x3-8x2 + 6x + 36 32, f(x) =-x3 + 7x-6 For each function use the leading coefficient test 20. f(x) = (x-1 )2(x +3)2 22, f(x) = x6 24, f(x) = x2-5x-6 28. fx)3x2-x+ I to determine whether y or y- as x-> 00, 33. y = 2x3-z?+9 35, y =-3x4 + 5 34. y=-3x + 7 36, y = 6x4-5x2-1

Explanation / Answer

We know that if f(x) = anxn+an-1xn-1 +…+a1x +a0 , then we have the following scenarios:

When n is odd and an is positive, then y = f(x) as x

When n is odd and an is negative, then y = f(x) - as x

28. Here, the degree of f(x) is 3 (odd) and the coefficient of x3 is positive. Hence f(x) = x3-x2-x+1 as x .

31. Here, the degree of f(x) is 3 (odd) and the coefficient of x3 is negative. Hence f(x) = -2x3-8x2+6x+36 - as x .

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