One-Sample Statistics N Mean Std. Deviation Std. Error Mean HOW MUCH FEAR- BEING
ID: 3135540 • Letter: O
Question
One-Sample Statistics
N
Mean
Std. Deviation
Std. Error Mean
HOW MUCH FEAR- BEING ROBBED OR MUGGED ON STREET
2231
5.00
3.280
.069
One-Sample Test
Test Value = 0
t
df
Sig. (2-tailed)
Mean Difference
95% Confidence Interval of the Difference
Lower
HOW MUCH FEAR- BEING ROBBED OR MUGGED ON STREET
72.028
2230
.000
5.001
4.87
One-Sample Test
Test Value = 0
95% Confidence Interval of the Difference
Upper
HOW MUCH FEAR- BEING ROBBED OR MUGGED ON STREET
5.14
Suppose we want to determine if the mean for fear of being robbed in our data set is different from a hypothetical population mean for fear of being robbed equal to 7. Be sure that your alpha level is .05 (95% confidence interval). Interpret your results. What do you conclude?
One-Sample Statistics
N
Mean
Std. Deviation
Std. Error Mean
HOW MUCH FEAR- BEING ROBBED OR MUGGED ON STREET
2231
5.00
3.280
.069
Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u = 7
Ha: u =/ 7
As we can see, this is a two tailed test.
Thus, getting the critical t,
df = n - 1 = 2230
tcrit = +/- 1.961028351
Getting the test statistic, as
X = sample mean = 5
uo = hypothesized mean = 7
n = sample size = 2231
s = standard deviation = 3.28
Thus, t = (X - uo) * sqrt(n) / s = -28.8008919
Also, the p value is
p = 2.3532E-155
As |t| > 1.96, and P < 0.05, we REJECT THE NULL HYPOTHESIS.
Hence, there is significant evidence at 0.05 level that the mean for fear of being robbed in our data set is different from a hypothetical population mean for fear of being robbed equal to 7. [CONCLUSION]
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