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Twenty laboratory mice were randomly divided into two groups of 10. Each group w

ID: 3134772 • Letter: T

Question

Twenty laboratory mice were randomly divided into two groups of 10. Each group was fed according to a prescribed diet. At the end of 3 weeks, the weight gained by each animal was recorded. Do the data in the following table justify the conclusion that the mean weight gained on diet B was greater than the mean weight gained on diet A, at the = 0.05 level of significance? Assume normality. (Use Diet B - Diet A.)


(a) Find t. (Give your answer correct to two decimal places.)


(ii) Find the p-value. (Give your answer correct to four decimal places.)

Diet A 11 12 5 9 14 12 14 7 11 13 Diet B 14 16 22 23 7 11 23 14 6 22

Explanation / Answer

a)

Formulating the null and alternative hypotheses,              
              
Ho:   ud   >=   0  
Ha:   ud   <   0  
At level of significance =    0.01          
As we can see, this is a    left   tailed test.      
              
Calculating the standard deviation of the differences (third column):              
              
s =    7.788880964          
              
Thus, the standard error of the difference is sD = s/sqrt(n):              
              
sD =    2.463060427          
              
Calculating the mean of the differences (third column):              
              
XD =    5          
              
As t = [XD - uD]/sD, where uD = the hypothesized difference =    0   , then      
              
t =    2.029994857   [ANSWER]

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ii)      
              
df = n - 1 =    9          
              
              
Also, using p values, as this is right tailed,              
              
p =        0.03646752   [ANSWER, P VALUE]

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As P < 0.05, we reject Ho.

There is significant evidence at 0.05 level that the mean weight gained on diet B was greater than the mean weight gained on diet A. [CONCLUSION]  
              

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