A genetic experiment involving peas yielded one sample of offspring consisting o

Question

A genetic experiment involving peas yielded one sample of offspring consisting of 448 green peas and 147 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 27% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses?

H0 : p = 0.27

H1: p0.27

What is the test statistic? z= ____

Explanation / Answer

Sample proportion, p = 147/448 = 0.3281

H0 : p = 0.27

H1: p0.27

test statistics = (0.3281-0.27)/sqrt(0.3281*(1-0.3281)/448) = 2.6191

P-value = 0.00441*2 = 0.00882

Since p-value (0.00882) < significance level (0.01), we reject the null hypothesis p = 0.27.

We reject the claim that 27% of offspring peas will be yellow

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