For each of the following, calculate mu_x, sigma_x^2, and sigma_x by using the f
ID: 3132090 • Letter: F
Question
For each of the following, calculate mu_x, sigma_x^2, and sigma_x by using the formulas given in this section. Then (1) interpret tho meaning of mu_x and (2) find the probability that x falls in the interval (mu_x plusminus 2 sigma_x]. Thirty percent of oil customers who enter a store will make a purchase. Suppose that six customers enter the store and that these customers make independent purchase decisions. Where x = the number of the six customers who will make a purchase. (Negative amounts should be Indicated by a minus sign. Round your answers to 4 decimal places.) The customer service department for a wholesale electronics outlet claims that 90 percent of all customer complaints are resolved to the satisfaction of the customer In order to test this claim a random sample of 15 customers who have filed complaints is selected Where x = the number of 15 sampled customers whose complaints were resolved to the customer's satisfaction (Round your answers to 4 decimal places.) The united states Golf association requires that the weight of a golf ball must not exceed 1.62 oz. The association periodically checks golf balls sold in the united states by sampling specific brands stocked by pro shops. Suppose that a manufacturer claims that no more than 1 percent of its brand of golf balls exceed 1.62 oz. in weight. Suppose that 24 of this manufacturer's golf balls are randomly selected. Where x = the number of the 24 randomly selected golf that exceed 1.62 oz. in weight. (Round your answer to 4 decimal places. Negative amounts should be indicated by a minus sign.)Explanation / Answer
a).
p=0.30, n=6
Expectation = np = 1.8
Variance = np(1 - p) = 1.26
Standard deviation = 1.1225
mean±2*sd = (-0.4450, 4.0450)
p( x 4) = 0.9891
b).
p=0.90, n=15
Expectation = np = 13.5
Variance = np(1 - p) = 1.35
Standard deviation = 1.1619
mean±2*sd = ( 11.1762, 15.8238)
p( x 12) = 0.9444
c).
p=0.01, n=24
Expectation = np = 0.24
Variance = np(1 - p) = 0.2376
Standard deviation = 0.4874
mean±2*sd = ( -0.7348, 1.2148)
p( x 1) = 0.9761
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