please show work needed to find final answer...thumbs up if typed/ or written ne
ID: 3132037 • Letter: P
Question
please show work needed to find final answer...thumbs up if typed/ or written neatly.
Explanation / Answer
a) Total = 1
Yes add up to 1
b) P(x=4) = 0.2592
c) P(X<2) = 0.0102+0.0768
= 0.0870
d) P(X>=3) = 0.3456+0.2592+0.0778
= 0.6826
e) E(x) = mean of x
= sum of x p(x)
= 0+0.0768+0.4608+1.0368+1.0368+0.3890
= 3.0002
This is the value of average which is expected
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