he owner of a golf course wants to determine if his golf course is more difficul

Question

he owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 26 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 26 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is -1.18 strokes and the standard deviation of the differences is 9.373 strokes. The owner uses this information to calculate the 90% confidence paired t-interval of (-4.32, 1.96). Which statement is the correct interpretation of this interval?

Question 10 options:

A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 35 patients were recorded before administering the drug and after. The average difference in cholesterol levels (after - before) was 4.33 mg/dL with a standard deviation of 6.457 mg/dL. Using this information, the calculated 95% confidence paired-t interval is (2.112, 6.548) Which of the following is the best interpretation of this interval?

Question 11 options:

Question 12 (1 point)

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 29 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 29 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is 0.066 and the standard deviation of the differences is 5.148. If he calculates a 99% confidence interval to estimate the average difference in scores for all golfers, what is the margin of error of the interval?

Question 12 options:

We are 90% confident that the difference between the average score on the owner's golf course and the average score on the friend's golf course is between -4.32 and 1.96.

1) The proportion of all golfers that had a difference in scores between the two courses is 90%. 2) We are certain the the average difference in scores between the two courses for all golfers is between -4.32 and 1.96. 3) We are 90% confident that the average difference in the scores of the golfers sampled is between -4.32 and 1.96. 4) We are 90% confident that the average difference in scores between the two courses for all golfers is between -4.32 and 1.96.

A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 35 patients were recorded before administering the drug and after. The average difference in cholesterol levels (after - before) was 4.33 mg/dL with a standard deviation of 6.457 mg/dL. Using this information, the calculated 95% confidence paired-t interval is (2.112, 6.548) Which of the following is the best interpretation of this interval?

Question 11 options:

1) We are 95% confident that the average difference in cholesterol levels between those who would take the drug and those who would not is between 2.112 and 6.548. 2) The proportion of all patients that had a difference in cholesterol levels between those on the drug and those who are not is 95%. 3) We are 95% confident that the difference between the average cholesterol level for those on the drug and the average cholesterol level for those not on the drug is between 2.112 and 6.548. 4) We are 95% confident that the average difference in the cholesterol levels of the patients sampled is between 2.112 and 6.548. 5) We are certain the the average difference in cholesterol levels between those who would take the drug and those who would not is between 2.112 and 6.548. Save

Question 12 (1 point)

5)

The owner of a golf course wants to determine if his golf course is more difficult than the one his friend owns. He has 29 golfers play a round of 18 holes on his golf course and records their scores. Later that week, he has the same 29 golfers play a round of golf on his friend's course and records their scores again. The average difference in the scores (treated as the scores on his course - the scores on his friend's course) is 0.066 and the standard deviation of the differences is 5.148. If he calculates a 99% confidence interval to estimate the average difference in scores for all golfers, what is the margin of error of the interval?

Question 12 options:

1) 2.3536 2) 2.6416 3) 0.956 4) 2.635 5) 0.6611

We are 90% confident that the difference between the average score on the owner's golf course and the average score on the friend's golf course is between -4.32 and 1.96.

Explanation / Answer

10.

Note that when we do confidence intervals, we do it not just for the sample, but for the whole population.

Hence,

OPTION 4: We are 90% confident that the average difference in scores between the two courses for all golfers is between -4.32 and 1.96. [ANSWER]

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11.

Note that when we do confidence intervals, we do it not just for the sample, but for the whole population.

OPTION 1: We are 95% confident that the average difference in cholesterol levels between those who would take the drug and those who would not is between 2.112 and 6.548 [ANSWER]

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