Looking at First-year student sleep Example: In the general population of U.S./C
ID: 3129824 • Letter: L
Question
Looking at First-year student sleep Example:
In the general population of U.S./Canadian university students: – Average nightly hours of sleep = 7 – Standard deviation = 1.5
In a sample of first-year students from the Making the Transition study: – n = 167 – Average nightly hours of sleep = 6.68 – Standard error of the mean: 1.5/sqrt167=0.12
H0: First-year students from Making the Transition sleep the same number of hours at night compared to the population
H1: First-year students from Making the Transition do not get the same hours of sleep at night as students in the general population
xlower = 7 + (1.96)(.12) = 6.76
xupper = 7 + (1.96)(.12) = 7.24
Question is: We reported a sample size of 167, but suppose we only collected data from 90 students instead. If we obtained the same sample mean of 6.68 hours of sleep, would our decision to reject/retain the null hypothesis change? Why or why not?
Explanation / Answer
In the general population of U.S./Canadian university students: – Average nightly hours of sleep = 7 – Standard deviation = 1.5
In a sample of first-year students from the Making the Transition study: – n = 167 – Average nightly hours of sleep = 6.68 – Standard error of the mean: 1.5/sqrt167=0.12
H0: First-year students from Making the Transition sleep the same number of hours at night compared to the population
H1: First-year students from Making the Transition do not get the same hours of sleep at night as students in the general population
xlower = 6.68 + (1.96)(.12) = 6.45
xupper =6.68 + (1.96)(.12) = 6.91
The 95% CI=(6.45,6.91) does not contains population mean 7, we reject null hypothesis
Question is: We reported a sample size of 167, but suppose we only collected data from 90 students instead. If we obtained the same sample mean of 6.68 hours of sleep, would our decision to reject/retain the null hypothesis change? Why or why not?
For sample size 90, Standard error of the mean: 1.5/sqrt(90)=0.16
xlower = 6.68 + (1.96)(.16) = 6.37
xupper =6.68 + (1.96)(.16) = 6.99
The 95% CI=(6.37,6.99) does not contains population mean 7, we reject null hypothesis
For the sample size of 90, we reject the null hypothesis.
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