While playing Texas Hold’em I am handed two aces. After receiving my cards there
ID: 3129316 • Letter: W
Question
While playing Texas Hold’em I am handed two aces. After receiving my cards there is a betting round. Subsequently, 3 cards, called “the flop” are dealt face up in the center of the table. What is the probability: atleast 1 card is of my denomination (hint : complementation rule) ; gives you “trips” that is contains exactly 1 card of my denomination and 2 other unpaired cards; gives me “quads” 2 cards of my denomination; and then gives me a “boat”, that is contains 1 card of my denomination and 2 cards of another denomination?Explanation / Answer
In total there are 13 denominations => (A,K,Q,J,10,9,8,7,6,5,4,3,2)
1.) P(At least 1 card of your denomination) = P(X=1) + P(X=2)
= 1/50 +2/50
= 3/50
= 0.06
2.) P(trips) = P(Exactly 1 Ace) * P(2 unpaired cards)
P(trips) = P(Exactly 1 Ace) *[P(2 unpaired cards)]
= 1/50 * 48/49 * 45/48
= 0.018
3.) P(quads) = 2/50
= 0.04
4.) P(boat) = 1/50 * 48/49 * 3/48
= 0.0012
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