24. Use technology to help you test the claim about the population mean, , at th
ID: 3129246 • Letter: 2
Question
24. Use technology to help you test the claim about the population mean, , at the given level of significance, , using the given sample statistics. Assume the population is normally distributed.
Claim: > 1190; = 0.06; = 202.07. Sample statistics: x = 1222.56, n = 200
Identify the null and alternative hypotheses. Choose the correct answer below.
A
H0:1222.56
B
H0:>1222.56
Ha:>1222.56
Ha:1222.56
C
H0:1190
D
H0:1222.56
Ha:>1190
Ha:<1222.56
E
H0:1190
F
H0:>1190
Ha:<1190
Ha:1190
Calculate the standardized test statistic.
The standardized test statistic is ____ (Round to two decimal places as needed.)
Determine the P-value.
P = ____ (Round to three decimal places as needed.)
Determine the outcome and conclusion of the test.
(Reject or Fail to reject) H0. At the 6% significance level, there (is or is not) enough evidence to (reject or support) the claim.
A
H0:1222.56
B
H0:>1222.56
Ha:>1222.56
Ha:1222.56
C
H0:1190
D
H0:1222.56
Ha:>1190
Ha:<1222.56
E
H0:1190
F
H0:>1190
Ha:<1190
Ha:1190
Explanation / Answer
. Use technology to help you test the claim about the population mean, , at the given level of significance, , using the given sample statistics. Assume the population is normally distributed.
Claim: > 1190; = 0.06; = 202.07. Sample statistics: x = 1222.56, n = 200
Identify the null and alternative hypotheses. Choose the correct answer below.
A
H0:1222.56
B
H0:>1222.56
Ha:>1222.56
Ha:1222.56
C
H0:1190
D
H0:1222.56
Ha:>1190
Ha:<1222.56
E
H0:1190
F
H0:>1190
Ha:<1190
Ha:1190
Calculate the standardized test statistic.
The standardized test statistic is 2.28 (Round to two decimal places as needed.)
Determine the P-value.
P = 0.011 (Round to three decimal places as needed.)
Determine the outcome and conclusion of the test.
(Reject) H0. At the 6% significance level, there (is) enough evidence to (support) the claim.
Z Test of Hypothesis for the Mean
Data
Null Hypothesis m=
1190
Level of Significance
0.06
Population Standard Deviation
202.07
Sample Size
200
Sample Mean
1222.56
Intermediate Calculations
Standard Error of the Mean
14.2885
Z Test Statistic
2.2788
Upper-Tail Test
Upper Critical Value
1.5548
p-Value
0.0113
Reject the null hypothesis
A
H0:1222.56
B
H0:>1222.56
Ha:>1222.56
Ha:1222.56
C
H0:1190
D
H0:1222.56
Ha:>1190
Ha:<1222.56
E
H0:1190
F
H0:>1190
Ha:<1190
Ha:1190
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.