This Question: 1 pt 15 of 15 (0 complete Test whether 1S P2 at the :0 02 level o
ID: 3127822 • Letter: T
Question
This Question: 1 pt 15 of 15 (0 complete Test whether 1S P2 at the :0 02 level of sigificance for the sample data shown in Cick the icon to view the data tabla Determine the null and alternative hypothesis for this test the accompanying table. Assume that the populations are normally distributed Click the icoan to view the Sample Data Population 2 25 114.5 13.2 Population 1 103.5 12.3 Print Done Detenine the P-value for this hy pothesis test. P-Round to three decimal places as needed) State the appropriate conclusion. Choose the correct answer below Click to select your answer(s)Explanation / Answer
Formulating the null and alternative hypotheses,
Ho: u1 - u2 = 0
Ha: u1 - u2 < 0 [ANSWER, B]
********************************
At level of significance = 0.05
As we can see, this is a left tailed test.
Calculating the means of each group,
X1 = 103.5
X2 = 114.5
Calculating the standard deviations of each group,
s1 = 12.3
s2 = 13.2
Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):
n1 = sample size of group 1 = 33
n2 = sample size of group 2 = 25
Thus, df = n1 + n2 - 2 = 56
Also, sD = 3.399138928
Thus, the t statistic will be
t = [X1 - X2 - uD]/sD = -3.236113684
where uD = hypothesized difference = 0
Thus, using p values,
p = 0.001018281 [ANSWER, P VALUE]
**********************************
As P < 0.02, we REJECT THE NULL HYPOTHESIS.
Hence,
OPTION B: Reject Ho. There is sufficient evidence... [ANSWER, B]
*****************************************************
Hi! If you use another method/formula in calculating the degrees of freedom in this t-test, please resubmit this question together with the formula/method you use in determining the degrees of freedom. That way we can continue helping you! Thanks!
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.