K section o. Ex. Score: 0 of 1 pt Nortmal Probabilty Dist 6.3.28 HW Score: 64.71
ID: 3127404 • Letter: K
Question
K section o. Ex. Score: 0 of 1 pt Nortmal Probabilty Dist 6.3.28 HW Score: 64.71% (11 of 17 pts) Assume that human body temperatures are normally distributed with a mean of 98.2 0.61 13 of 17 0omplete and a standard deviation of a. A hospital uses 100.6F as the lowest temperature considered to be a fever. What percentage of normal and healthy persons would be considered to have a fever? Does this percentage suggest that a cutoff of 100.6F is appropriate? b. Physicians want to select a minimum temperature for requiring further medical tests. What should that temperature be,ifwe want only 50% of healthy people to exceed it? (Such aresult is a false positive, meaning that the test result is positive, but the subject is not really sick.) The percentage of normal and healthy persons considered to have a fever is (Round to two decimal places as needed.) Check Answer Enter your answer in the answer box, then dick Check Answer 2 parts remaining 21Explanation / Answer
MEAN = 98.23
STANDARD DEVIATION = 0.61
A)
For x = 100.6, z = (100.6 - 98.23) / 0.61 = 3.88
Hence P(x > 100.6) = (P> 3.88) = [total area] - [area to the left of 3.88]
= 1 - 0.9999 = 0.0001
= 0.01%
B)5% HEALTHY = 0.95 CHANCES
HENCE Z SCORE FOR O.95 = 1.65
X = MEAN + Z*STANDARD DEVIATION = 98.23 +1.65*0.61 = 99.23
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