Rafflesia arnoldii is one of the strangest and rarest plants on Earth. It lives
ID: 3127343 • Letter: R
Question
Rafflesia arnoldii is one of the strangest and rarest plants on Earth. It lives as a parasite on the Tetrastigma vine, which grows only in primary undisturbed rainforests of Sumatra and Borneo in the Indonesia Archipelago. Its real claim to fame is that it produces the world’s largest flowers. Individual blossoms can be nearly a meter in diameter and can weigh up to 11 kilograms. It doesn’t produce leaves, stems, or roots. Other than the gigantic blooms the plant exists only as filaments within its unfortunate host. Because this plant is so rare it is considered endangered. During a recent expedition fourteen flowers were discovered and measured. Below are the summary data for this sample.
(a) Calculate the mean and standard deviation for the flower diameter measured in centimeters.
(b) For the flower weights, measured to the nearest kilogram, calculate the variance, standard deviation, and standard error.
The answers are:
(a) X = 91.9 cm, and s = 7.6 cm.
(b) s 2 = 8.88 kg2 , s = 3.0 kg, and standard error 0.832 kg.
I need to understand how to get the answers, thank you!
diameter weight SumXi = 1286 cm mean = 9.5 kg sumXi^2 = 118, 876 cm2 sumXi^2 = 1379 kg2Explanation / Answer
(a)The mean is: sum Xi/n=1286/14=91.85
The standard deviation is: square root of(sum Xi^2/n-mean^2)
=sq rt(118876/14-91.85^2)
=7.39
(b)The variance is: (sum Xi^2/n-mean^2)
=1379/14-9.5^2=8.25
The standard deviation is sq rt of 8.25=2.87
The standard error is 2.87/sq rt n
=2.87/3.74=0.76
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