Two methods, A and B , are available for teaching a certain industrial skill. Th

Question

Two methods, A and B, are available for teaching a certain industrial skill. There is an 80% chance of successfully learning the skill if method A is used, and a 95% chance of success if method B is used. However, method Bis substantially more expensive and is therefore used only 25% of the time (method A is used the other 75% of the time). The following notations are suggested:

A—Method A is used.

B—Method B is used.

L—The skill was learned successfully.

What is the probability that a randomly chosen worker will learn the skill successfully?

P(L) = 0.75 * 0.80 = 0.60

P(L) = 0.25 * 0.95 = 0.2375

P(L) = 0.75 * 0.25 + 0.80 * 0.95 = 0.9475

P(L) = 0.75 * 0.95 + 0.25 * 0.80 = 0.9125

P(L) = 0.75 * 0.80 + 0.25 * 0.95 = 0.8375

AND:

Which of the following is the correct representation of the information that is provided to us?

P(A) = 0.75, P(B) = 0.25, P(L | A) = 0.80, P(L | B) = 0.95

P(A) = 0.75, P(B) = 0.25, P(A | L) = 0.80, P(B | L) = 0.95

P(A) = 0.75, P(B) = 0.25, P(A and L) = 0.80, P(B and L) = 0.95

P(A | L) = 0.75, P(B | L) = 0.25, P(L | A) = 0.80, P(L | B) = 0.95

P(A and L) = 0.75, P(B and L) = 0.25, P(L | A) = 0.80, P(L | B) = 0.95

Explanation / Answer

P(L) = 0.75 * 0.80 + 0.25 * 0.95 = 0.8375

P(A) = 0.75, P(B) = 0.25, P(L | A) = 0.80, P(L | B) = 0.95

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.