David Mash Icy teaches two undergraduate statistics. Courses at Kansas College.
ID: 3126790 • Letter: D
Question
Explanation / Answer
a) First draw is frrom Stat 201,
So, P (Junior on first draw) = 3 / 10 = 0.3
b)
If first card is a sophomore., the professor again draws from STAT 201
Since, it is sampling with replacement,
the probability of junior on second draw = 3 / 10 = 0.30
c)
If there is a juniors name on first draw, the professor will choose from STAT 301
P (Junior in 2nd draw) = 8/10 = 0.8
d)
Sophomore's name on both draws indicate both are taken from STAT 201
Thus,
required probability = 0.7 * 0.7
= 0.49
e)
Junior's name on both draws implies first one is from STAT 201 and next from STAT 301
thus, required probability = 0.3 * 0.8
= 0.24
f)
P ( One sophomore , one junior)
= (0.7 * 0.3) + (0.3 * 0.2)
= 0.27
Hope this helps.
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