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Save Score: 0.44 of 1 pt 5 0.6 (3 complete) HW Score: 61.57%, 3 69 of 6 pts 10.4

ID: 3124455 • Letter: S

Question

Save Score: 0.44 of 1 pt 5 0.6 (3 complete) HW Score: 61.57%, 3 69 of 6 pts 10.4.16-T Question Help I * Suppose the mean wait-time for a telephone reservation agent at a large airline is 43 seconds. A manager with the airline is concemed that business may be lost due to customers having to wait too long for an agent. To address this concem, the manager develops new airfine reservation policies that are intended to reduce the amount of time an agent needs to spend with each customer. A random sample of 250 customers results in a sample mean wait-time of 42.3 seconds with a standard deviation of 43 seconds. Using :0.05 level of significance, do you believe the new policies were effective in reducing wait time? Do you think the results have any practical significance? Determine the null and altemative hypothes es Ho 43 seconds H1 : (43 seconds Calculate the test statistic. Round to two decimal places as needed) Enter your answer in the answer box and then click Check Answer Check Answer Clear All parts remaining

Explanation / Answer

10.4.16

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

43

Level of Significance

0.05

Sample Size

250

Sample Mean

42.3

Sample Standard Deviation

4.3

Intermediate Calculations

Standard Error of the Mean

0.2720

Degrees of Freedom

249

t Test Statistic

-2.5739

Lower-Tail Test

Lower Critical Value

-1.6510

p-Value

0.0053

Reject the null hypothesis

Calculated t= -2.57 ( two decimals)

10.4.12

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

6

Level of Significance

0.1

Sample Size

49

Sample Mean

5.35

Sample Standard Deviation

2.4

Intermediate Calculations

Standard Error of the Mean

0.3429

Degrees of Freedom

48

t Test Statistic

-1.8958

Lower-Tail Test

Lower Critical Value

-1.2994

p-Value

0.0320

Reject the null hypothesis

Calculated t= -1.90 ( two decimals)

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

43

Level of Significance

0.05

Sample Size

250

Sample Mean

42.3

Sample Standard Deviation

4.3

Intermediate Calculations

Standard Error of the Mean

0.2720

Degrees of Freedom

249

t Test Statistic

-2.5739

Lower-Tail Test

Lower Critical Value

-1.6510

p-Value

0.0053

Reject the null hypothesis

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