“Arizona Best Pizzaria” made combo pizza that contains exactly 45 ounces of topp

Question

“Arizona Best Pizzaria” made combo pizza that contains exactly 45 ounces of toppings. The base has a fixed weight and is not considered in the calculation. The available toppings are listed below with their corresponding weight (in ounces). There can be multiple entries of each topping, as long as the total weight is equal to 45 ounces. [20 points]

Topping

Weight (ounces)

Pepperoni

Meatball

Basil

Olives

Chicken

5

10

7

3

8

         For example, a pizza can contain 1 topping of pepperoni, 2 toppings of meatball, 2 toppings of basil, and 2 toppings of olives : 1*5 + 2*10 + 2*7 + 2*3 = 45 (ounces)

         A pizza cannot contain 6 toppings of chicken : 6 * 8 = 48 > 45

         A pizza cannot contain only 3 toppings of meatball : 3*10 = 30 < 45

2.1    Define a rule pizza(P, M, B, O, C) to find out how many of each topping can be contained on a pizza, where P, M, B, O, and C are the numbers of the pepperoni, meatball, basil, olives, and chicken toppings, respectively.                                                                  [14]

2.2    Write a rule called q2 :- condition, to ask the following question (goal), so that the grader to type | ?- q2. To test the question.        [2]

| ?- pizza(1, 2, 2, 2, 2). Put all answers of the question in a comment in the file.

2.2    Write a rule called q3 :- condition, to ask the following question (goal), so that the grader to type | ?- q3. To test the question.        [2]

| ?- pizza(1, M, 1, O, C). Put all answers of the question in a comment in the file.

2.3    Write a rule called q3 :- condition, to ask the following question (goal), so that the grader to type | ?- q3. To test the question.        [2]

| ?- pizza(P, M, B, O, 1). Put all answers of the question in a comment in the file

Topping

Weight (ounces)

Pepperoni

Meatball

Basil

Olives

Chicken

5

10

7

3

8

Explanation / Answer

given

pepperoni 5

meatball 10

basil 7

olives 3

chicken 8

answer 2.1

for pepperoni

total waight 45/5=9

means 9 pepperoni toppings

for meatball=10*5=50>45 <10*4=40

4 so there only 4 topings of meatball

for basil:

7*6= 42

7*7=49

49>45>42

so only 6 topings of basil

for olives

53/3=15 means 15 topings of olives

for chicken

45/8=5.67

means 5 toppings can be used of chicken.

now 2.2: (pizza(1, 2, 2, 2, 2). Put all answers of the question in a comment in the file.

get the value

1 pepperoni= 5

2 meatballs= 20

2 basil =14

2 olives=6

2 chicken=16

total=61>45

now total waight should not>45

so conditions

1)5+20+14+6=45(1p,2m,2b,2o)

2 )20+6+16 =42<45(2m,2o,2c)

3) 5+14+6+16=41<45 (1p,2b,2c,2o)

now 2.2.1

now condition is

1,M,1,O,C

5+M+7+O+C<45

12+M+O+C<45

(1) M+2O+2C<33

10+6+16<33 =(1,1,1,2,2)

(2) 3m<33=(1p,3m,1b)

(3) 2m+o+c=20+3+8=31<33(1,2,1,1,1)

now 2.3

condition

(P0,M,B,O,1)

P+M+B+O+8<=45

P+M+B+O<=37

10+10+14+3=37

2P,1M,2B,1O,1C

0P+2M+2B+1O+1C=20+14+3+8=45

(2M,2B,10,1C)

SAME AS OTHERS CAN BE USED

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.