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O webassign netwebstudent/Assignment Responsesiast?depr 1604aa7o O Question Details sercpe 20 P.032. A conducting bar of length e moves to the right on two frictionless rails, as shown in the figure below. A uniform magnetic field directed into the page has a magnitude of 3.30 T. Assum 34 cm and 9.1 n. (a) At what constant speed should the bar move to produce an 8.6 mA current in the resistor? What is the direction of this induced current? Counterclockwise (b) At what rate is energy delivered to the resistor? (c) Explain the origin of the energy being delvered to the resistor Need Help? a 3 Type here to search O

Explanation / Answer

(a) the emf produced by moving bar is

V = B*l*v

l = 34 cm = 0.34m

we also know that from Ohm's law

V = IR

so Blv = IR

v = IR/Bl

= 8.6*10-3 *9.1 /(3.3*0.340) = 0.0697 m/s

(b) power delivered

P = I2 R = (8.6*10-3)2 * 9.1 = 6.73036*10-4 W

or 0.673036 mW

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