A bag contains 17 marbles: 10 purple and 7 green. The purple marbles are numbere

Question

A bag contains 17 marbles: 10 purple and 7 green. The purple marbles are numbered 1 through 10 and the green ones are numbered 11 through 17. If one marble is chosen, what is the probability that it is purple? If one marble is chosen, what is the probability that it is green? If one marble is chosen, what is the probability that it is both purple and even? If one marble is chosen, what is the probability that it is NOT both purple and even? If one marble is chosen, what is the probability that it is green or even? If one marble is chosen, what is the probability it is even, given that it is green? If two marble are chosen with replacement, what is the probability both are odd? If two marble are chosen without replacement what is the probability that the first is purple and the second is green? Give an example of two events that are mutually exclusive when one marble is chosen. If 89 marbles are chosen at random without replacement, what is the probability that at least one is purple?

Explanation / Answer

Solution: (12)

The probability of the first marble being purble : Number of total purple ball /(total number of ball)

= 10/34

the probability of the second marble being green = Number of total green ball / ( total number of ball after first drawn )

= 7/33

Multiply the probabilities together to determine the probability of both events occurring = (10/34) * (7/33)

= 35/ 561

Answer: 35 /561 = 0.0624 ( approx)

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