Use matrices to solve the system. (If there is no solution, enter NO SOLUTION, I

Question

Use matrices to solve the system. (If there is no solution, enter NO SOLUTION, If there are infinitely many solution express x, y, and z in terms of the {2x + 6y - 4z = -6 x + 3y - 2z = 4 2x + y - 3z = 4 (x, y, z) = Use matrices to solve the system. (If there is no solution, enter NO SOLUTION, If there are infinitely many solution express x, y, and z in terms of the {x + 3y + z = 0 x + y - z = 0 2x - 4y - 8z = 0 (x, y, z) = Use matrices to solve the system. (If there system has infinitely many solutions, express your answer in terms of c, where x = x(c), y = y(c) and z = c. If the {4x - 3y = -13 2x + y = 1 -x + y = 4 (x, y) =

Explanation / Answer

Answer to the question is as follows:

For the 1st Question, subtract 1st equation from 2nd in the first step:

you will get RHS is not equal to LHS

or 0 = -14, which is not possible

Hence, the answer to this set of equations is NO SOLUTION

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