I need 27-32 Two dice, one green and one yellow, are rolled. in each of Exercise
ID: 3120997 • Letter: I
Question
I need 27-32
Explanation / Answer
Dear Student Thank you for using Chegg !! Given that two dice (1 green and 1 yellow) are rolled 27) Probability that the sum is 5 given that green one is not 1 and yellow one is 1 Conditiona probability of even A given event B is P(A/B) = P (A & B) / P(B) P(A) = Number of ways to get sum 5 when two dice are rolled 1,4 2,3 3,2 4,1 => 4/36 P(B) = Probabilty that Green is not 1 and yellow is 1 2,1 3,1 4,1 5,1 6,1 = 5/36 P (A & B) / P(B) = 1/5 (Since only one of the case listed in P(B) is also available in P(A), therefore P(A&B) = 1 Solution Now since A&B is not a null set (In fact equal to (4,1)), therefore the two events are not independent As per Chegg guidelines an expert can answer maximum one question at a time.
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