E Question Help 7.6.7 Suppose you have 3 jars with the following contents. Jar 1

Question

E Question Help 7.6.7 Suppose you have 3 jars with the following contents. Jar 1 has 1 white ball and 1 black ball. Jar 2 has 2 white balls and 1 black ball. Jar 3 has 1 white ball and 2 black balls. One jar is to be selected, and then 1 ball is to be drawn from the selected jar. The probabilities of selecting the first, second, and third jars are 1/3, 1/2, and 1/6 respectively. Find the probability the ball was drawn from J 1, given that the ball is white. ar What is the probability the ball was drawn from Jar 1, given that the ball is white? (Simplify your answer. Type an integer or a fraction.)

Explanation / Answer

7.6.7 solution

Given:   Jar 1 :- 1 whight ball and 1 black ball; 1/3 probability

Jar 2 :- 2 whight ball and 1 black ball; 1/2 probability

Jar 3 :- 1 whight ball and 2 black ball; 1/6 probability

now the probability to drawn a whight ball from Jar 1 = (jar's probability)( ball's probability of that jar)

= (1/3)(1/2) = 1/6 .............answer....

7.6.9 solution:

Before test; good workers percent = 90%

and poor workers percent = 10%

percent of workers who pass test; from good workers = 0.90* 0.90 (of the good workers 90% pass it)

=0.81 or 81%

from poor workers = 0.10*0.20 ( of the poor workers 20% pass it)

= 0.02 or 2%

Now, if the company makes the test part ot its hiring procedure and as well as previous requirements then the percent of people who will be hired = 81% + 2% = 83%

Now, 90% of new hires turn to be good workers, so that is = 0.90*0.83 = 0.7470 or 74.7% that is 75%

Related Questions

Navigate

• Browse (All)
• Browse E
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.